Arrange the following compounds in increasing order of their boiling points.
$C H_{3} C H O, C H_{3} C H_{2} O H, C H_{3} O C H_{3}, C H_{3} C H_{2} C H_{3}$

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Solution

As the intermolecular force increases, boiling point increases. Strength of intermolecular force is as follows:
$H - bonding > dipole-dipole > Dispersion force$

Alcohol has the highest boiling point due to more extensive intermolecular $H - bonding$ .
Aldehyde is more polar than ether. So, ethanal has higher boiling point than methoxy methane.

Alkane has the lowest boiling point due to complete non-polar nature(it has only London dispersion force).

Hence, increasing order of boiling points of compounds is given below-
$C H_{3} C H_{2} C H_{3} < C H_{3} O C H_{3} < C H_{3} C H O < C H_{3} C H_{2} O H$

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