Question

Arrange the following compounds in increasing order of their boiling points.
I. $C{H}_{3}C{H}_{2}C{H}_{2}Br$
II. $C{H}_{3}C{H}_{2}C{H}_{2}C{H}_{2}Br$
III.$(C{H}_3{)}_{2}CHC{H}_{2}Br$
IV. $(C{H}_3{)}_{3}CBr$

• A. $II<I<III<IV$
• B. $III<I<IV<II$
• C. $IV<III<II<I$
• D. $I<IV<III<II$

Answer 1

The correct option is D $I<IV<III<II$

Boiling points increases as the number of carbon atoms increases in the alkyl halides. Therefore the B.P of II, III and IV with four carbon atoms is higher than that of I with three carbon atoms. Further, the B.P decreases with the number of branches. Thus the B.P of the four alkyl halides increases in the order I$<$ IV$<$ III$<$ II.