Arrange the following compounds in increasing order of their ionic character.
$S n C l_{2}, S n C l_{4}, S i C l_{4}, S n F_{4}, S n F_{2}$

S n F_{2} < S n C l_{2} < S n C l_{4} < S i C l_{4}

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S n F_{2} < S n C l_{2} < S i C l_{4} < S i C l_{4}

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S n F_{2} < S n C l_{2} < S n C l_{4} < S i F_{2}

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S n F_{2} < S n C l_{2} < S n F_{4} < S i C l_{4}

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Solution

The correct option is A $S n F_{2} < S n C l_{2} < S n C l_{4} < S i C l_{4}$
Lattice enthalpy $\propto$ Covalent character
Lattice enthalpy $\propto \frac{1}{S i z e o f c a t i o n s, a n i o n s}$
Lattice enthalpy: $S n F_{2} > S n C l_{2} > S n C l_{4} > S i C l_{4}$
Ionic character: $S i C l_{4} > S n C l_{4} > S n C l_{2} > S n F_{2}$

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