Arrange the following compounds in terms of increasing polarity:
$H C N, N a C l, {C l}_{2}$

N a C l < H C N < C l_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

N a C l < C l_{2} < H C N

No worries! We‘ve got your back. Try BYJU‘S free classes today!

H C N < C l_{2} < N a C l

No worries! We‘ve got your back. Try BYJU‘S free classes today!

{C l}_{2} < H C N < N a C l

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D ${C l}_{2} < H C N < N a C l$
$C l_{2}$ has the same atoms bonded, hence the polarity is 0, whereas, the H-CN bond is notpolar due to the difference in the electronegativity of the H and CN groups or atoms.
NaCl has very high electronegative difference, as Na is metal and Cl is non-metal.
Hence order is as follows :
$C l_{2} < H C N < N a C l$

Suggest Corrections

Similar questions

Balance

NaCl + H2O =NaOH + H2O + Cl2

2 N a O H + C l_{2} \to N a C l +

+ H_{2} O

N a_{2} S O_{3} + 2 H C l \to 2 N a C l + H_{2} O +

C l_{2} + 3 F_{2} 573 K - -- \to

C l_{2}

C l_{4}

C l_{2}

C l 4

+ C l_{2} \to N a C l + N a C l O_{3}

C l_{2}

Join BYJU'S Learning Program