Question

Arrange the following compounds in the increasing order of number of Oxygen(O) atoms.

(A) Plumbic carbonate

(B) Ferric chromate

(C) Zinc silicate

(D) Aluminum sulphite

• A. ACBD
• B. CADB
• C. ACDB
• D. BDAC

Answer 1

The correct option is D

BDAC

Explanation:

Compound name	Molecular Formula	Number of Oxygen atom present
(A) Plumbic carbonate	$\mathrm{Pb}{\left({\mathrm{CO}}_3\right)}_2$	6
(B) Ferric chromate	${\mathrm{Fe}}_2{\left({\mathrm{CrO}}_4\right)}_3$	12
(C) Zinc silicate	${\mathrm{Zn}}_2{\mathrm{SiO}}_4$	4
(D) Aluminum sulphite	${\mathrm{Al}}_2{\mathrm{S}}_3{\mathrm{O}}_9$	9

On the basis of number of Oxygen atom the correct order is $B>D>A>C$

Hence the correct answer is (D).