Arrange the following compounds in the increasing order of their densities.

(I) < (II) < (III) < (IV)

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(I) < (III) < (IV) < (II)

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(IV) < (III) < (II) < (I)

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(II) < (IV) < (III) < (I)

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Solution

The correct option is A (I) < (II) < (III) < (IV)
At constant volume, the density of the compound is directly proportional to Molar mass of the compound.
Density, $D \propto M$
order of Molar mass, $(I) < (I I) < (I I I) < (I V)$
$∴$ The order of density is $(I) < (I I) < (I I I) < (I V)$

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