Arrange the following alcohols in order of increasing ease of dehydration
$C H_{3} C H_{2} O H$ $C_{6} H_{5} C H_{2} O H$
I II

$C l_{3} C C H_{2} O H$ $F_{3} C C H_{2} O H$
III IV

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Arrange the following compounds in their decreasing order of boiling points: I. C9H20 II. C8H18 III.(CH3)2C−(CH2)4−CH3 IV. CH3−CH3|C|CH3−CH3|C|CH3−CH3

The correct option is A (I)>(II)>(III)>(IV)The given hydrocarbons are alkanes. Greater the number of carbon atoms, higher the boiling point due to higher molecular mass. For the same number of carbon atoms, branching reduces the boiling point.

Arrange the following compounds in their decreasing order of boiling points:
$I . C_{9} H_{20} I I . C_{8} H_{18}$

$I I I . (C H_{3})_{2} C - (C H_{2})_{4} - C H_{3}$

$I V . C H_{3} - C H_{3} | C | C H_{3} - C H_{3} | C | C H_{3} - C H_{3}$

The correct option is A $(I) > (I I) > (I I I) > (I V)$
The given hydrocarbons are alkanes.
Greater the number of carbon atoms, higher the boiling point due to higher molecular mass. For the same number of carbon atoms, branching reduces the boiling point.