Question

Arrange the following decimals in ascending order:

$1.6,2.2,1.57,2.18,1.18,2.08$

Answer 1

Step 1: First make the number of digits after the decimal point equal by putting zeroes to the extreme right side of the decimal part, if required. The like decimals are $1.60,2.20,1.57,2.18,1.18,2.08.$

Step 2: Compare the whole number parts. The decimal with greater whole number is greater. Here, the whole numbers are $1,2,1,2,1,2$ respectively. In ascending order they are $1,1,1,2,2,2$.

Step 3: If the whole number parts are equal, compare the tenths digits. The decimal with the bigger digit in the tenths place is greater. In the numbers $2.18,2.08$ the hundredths digits are equal.

Step 4: If the tenths digits are equal, compare the hundredths digits, and so on. We get the results. Hence, the given decimals in ascending order are $\therefore 1.18<1.57<1.6<2.08<2.18<2.2.$