Question

Arrange the following decimals in descending order:

$51.2,52.1,15.2,152.2,215.2,25.12$

Answer 1

Step 1: First make the number of digits after the decimal point equal by putting zeroes to the extreme right side of the decimal part, if required. The like decimals are$51.20,52.10,15.20,152.20,215.20,25.12$.

Step 2: Compare the whole number parts. The decimal with greater whole number is greater. Here, the whole numbers are $51,52,15,152,215,25$. In descending order they are $215>152>52>51>25>15$. So, the decimal with $215$ as whole number is the largest.

Step 3: If the whole number parts are equal, compare the tenths digits. The decimal with the bigger digit in the tenths place is greater. Comparing tenths digits.

Step 4: If the tenths digits are equal, compare the hundredths digits, and so on. Comparing hundredths digits.

Hence, the given decimals in descending order are $215.2>152.2>52.1>51.2>25.12>15.2$.