Question

Question 67

Arrange the following exponents in descendig order.
$2^{2+3},(2^2{)}^3,2\times 2^2,\frac{3^5}{3^2},3^2\times 3^0,2^3\times 5^2$

Answer 1

We have
$2^{2+3}=2^5=2\times 2\times 2\times 2\times 2=32(2^2{)}^3=2^{2\times 3}=2^6=2\times 2\times 2\times 2\times 2\times 2=642\times 2^2=2^{1+2}=2^3=2\times 2\times 2=8\frac{3^5}{3^2}=3^{5-2}=3^3=3\times 3\times 3=273^2\times 3^0=3^{2+0}=3^2=3\times 3=92^3\times 5^2=2\times 2\times 2\times 5\times 5=8\times 25=200$

Thus, the required descending order will be
$2^3\times 5^2>(2^2{)}^3>2^{2+3}>\frac{3^5}{3^2}>3^2\times 3^0>2\times 2^2$