Question

Arrange the following fraction in ascending order.

$\frac{31}{41},\frac{31}{63},\frac{31}{100},\frac{31}{1000},\frac{31}{95},\frac{31}{105}$

Answer 1

We have, $\frac{31}{41},\frac{31}{63},\frac{31}{100},\frac{31}{1000},\frac{31}{95},\frac{31}{105}$

All the fractions have the same numerator therefore large denominator will have less value among the given fractions.

Clearly, $\frac{31}{1000}<\frac{31}{105}<\frac{31}{100}<\frac{31}{95}<\frac{31}{63}<\frac{31}{41}$

Hence, ascending order of given fractions are $\frac{31}{1000}<\frac{31}{105}<\frac{31}{100}<\frac{31}{95}<\frac{31}{63}<\frac{31}{41}$.