Question

Arrange the following fraction in ascending order.

$\frac{7}{11},\frac{3}{11},\frac{0}{11},\frac{4}{11},\frac{6}{11},\frac{9}{11},\frac{10}{11}$

Answer 1

We have, $\frac{7}{11},\frac{3}{11},\frac{0}{11},\frac{4}{11},\frac{6}{11},\frac{9}{11},\frac{10}{11}$

In the given fraction denominators of all is equal therefore large numerators among the given fractions will have the largest value.

Clearly, $\frac{0}{11}<\frac{3}{11}<\frac{4}{11}<\frac{6}{11}<\frac{7}{11}<\frac{9}{11}<\frac{10}{11}$

Hence, ascending order of given fractions are $\frac{0}{11}<\frac{3}{11}<\frac{4}{11}<\frac{6}{11}<\frac{7}{11}<\frac{9}{11}<\frac{10}{11}$.