Question

Arrange the following fractions in an ascending order.
$\frac{4}{7},\frac{4}{3},\frac{4}{6},\frac{4}{5}$

• A. $\frac{4}{3},\frac{4}{5},\frac{4}{6},\frac{4}{7}$
• B. $\frac{4}{7},\frac{4}{6},\frac{4}{5},\frac{4}{3}$
• C. $\frac{4}{7},\frac{4}{5},\frac{4}{6},\frac{4}{3}$
• D. $\frac{4}{3},\frac{4}{6},\frac{4}{5},\frac{4}{7}$

Answer 1

The correct option is B $\frac{4}{7},\frac{4}{6},\frac{4}{5},\frac{4}{3}$

L.C.M (7, 3, 6 & 5) = 210

Convert denominator of every fraction as 210.


$\frac{4}{7}=\frac{4\times 30}{7\times 30}=\frac{120}{210}$

$\frac{4}{3}=\frac{4\times 70}{3\times 70}=\frac{280}{210}$

$\frac{4}{6}=\frac{4\times 35}{6\times 35}=\frac{140}{210}$

$\frac{4}{5}=\frac{4\times 42}{5\times 42}=\frac{168}{210}$

$\frac{120}{210}<\frac{140}{210}<\frac{168}{210}<\frac{280}{210}$
$\frac{4}{7}<\frac{4}{6}<\frac{4}{5}<\frac{4}{3}$
Ascending order for the given fractions is $\frac{4}{7},\frac{4}{6},\frac{4}{5},\frac{4}{3}$