Question

Arrange the following fractions in ascending order : $\frac{5}{3},\frac{7}{4},\frac{6}{5}$ and $\frac{9}{8}$

• A. $\frac{9}{8}<\frac{6}{5}<\frac{5}{3}<\frac{7}{4}$
• B. $\frac{9}{8}<\frac{6}{5}<\frac{7}{4}<\frac{5}{3}$
• C. $\frac{7}{4}<\frac{5}{3}<\frac{9}{8}<\frac{6}{5}$
• D. $\frac{6}{5}<\frac{9}{8}<\frac{5}{3}<\frac{7}{4}$

Answer 1

Answer: (A)

$\frac{9}{8}<\frac{6}{5}<\frac{5}{3}<\frac{7}{4}$

Change the fractions into the decimals as follows:

$\frac{9}{8}=1.125$

$\frac{7}{4}=1.75$

$\frac{6}{5}=1.2$

$\frac{5}{3}=1.67$

Now arranging the fractions in the ascending order we get,

$\frac{9}{8}<\frac{6}{5}<\frac{5}{3}<\frac{7}{4}$