Question

Arrange the following fractions in descending order.

• A. Q, P, R, S, T
• B. Q, R, P, T, S
• C. S, T, P, R, Q
• D. T, S, R, P, Q

Answer 1

The correct option is D T, S, R, P, Q

Since these fractions are unlike, we need to first convert them to like fractions, by taking LCM of 5, 12, 9.

LCM of the denominators 5, 12 and 9 is: 2 × 2 × 3 × 3 × 5 = 180

$\frac{3}{5}$ = $\frac{3\times 36}{5\times 36}$ = $\frac{108}{180}$ = P

$\frac{11}{12}$ = $\frac{11\times 15}{12\times 15}$ = $\frac{165}{180}$ = Q

$\frac{7}{12}$ = $\frac{7\times 15}{12\times 15}$ = $\frac{105}{180}$ = R

$\frac{2}{5}$ = $\frac{2\times 36}{5\times 36}$ = $\frac{72}{180}$ = S

$\frac{2}{9}$ = $\frac{2\times 20}{9\times 20}$ = $\frac{40}{180}$ = T

So, $\frac{40}{180}$ < $\frac{72}{180}$ < $\frac{105}{180}$< $\frac{108}{180}$ < $\frac{165}{180}$

Hence, the ascending order of the given fractions is T, S, R, P, Q.