Question

Arrange the following fractions in descending order.
$\frac{4}{3},\frac{5}{6},\frac{7}{8},\frac{6}{5}$

• A. $\frac{4}{3}>\frac{6}{5}>\frac{5}{6}>\frac{7}{8}$
• B. $\frac{4}{3}>\frac{6}{5}>\frac{7}{8}>\frac{5}{6}$
• C. $\frac{6}{5}>\frac{4}{3}>\frac{7}{8}>\frac{5}{6}$
• D. $\frac{6}{5}>\frac{4}{3}>\frac{5}{6}>\frac{7}{8}$

Answer 1

The correct option is B $\frac{4}{3}>\frac{6}{5}>\frac{7}{8}>\frac{5}{6}$

LCM $(3,5,6,8)=120$
$\frac{4}{3}=\frac{4\times 40}{3\times 40}=\frac{160}{120}$
$\frac{5}{6}=\frac{5\times 20}{6\times 20}=\frac{100}{120}$
$\frac{7}{8}=\frac{7\times 15}{8\times 15}=\frac{105}{120}$
$\frac{6}{5}=\frac{6\times 24}{5\times 24}=\frac{144}{120}$
So, $\frac{4}{3}>\frac{6}{5}>\frac{7}{8}>\frac{5}{6}$