Question

Arrange the following fractions in descending order

$\frac{5}{6},\frac{7}{8},\frac{11}{12},\frac{15}{16}$

Answer 1

Step 1:- Converting all fraction into equivalent fraction,

Given fractions are $\frac{5}{6},\frac{7}{8},\frac{11}{12},\frac{15}{16}$

L.C.M. of $6,8,12,16$ is $48$

⇒ $\frac{5\times 8}{6\times 8}=\frac{40}{48}$ , $\frac{7\times 6}{8\times 6}=\frac{42}{48}$ , $\frac{11\times 4}{12\times 4}=\frac{44}{48}$ , $\frac{15\times 3}{16\times 3}=\frac{45}{48}$

Therefore, the fraction are $\frac{40}{48},\frac{42}{48},\frac{44}{48},\frac{45}{48}$

Step 2:- Arranging all fractions into descending order,

$45>44>42>40$

⇒ $\frac{45}{48}>\frac{44}{48}>\frac{42}{48}>\frac{40}{48}$

Therefore, ascending order of fraction is $\frac{15}{16},\frac{11}{12},\frac{7}{8},\frac{5}{6}$