Question

Arrange the following in an increasing order of strengths of oxidizing powers of the following:

• A. $N{i}^{2+}$
• B. $P{b}^{2+}$
• C. $C{d}^{2+}$
• D. $F{e}^{2+}$

Answer 1

Higher the reduction potential of $M^{2+}/M$, stronger is the oxidizing power of the ion.
$E_{N{i}^{2+}/Ni}^{\circ }=-0.26$
$E_{P{b}^{2+}/Pb}^{\circ }=-0.13$
$E_{C{d}^{2+}/Cd}^{\circ }=-0.40$
$E_{F{e}^{2+}/Fe}^{\circ }=-0.45$