Question

Arrange the following in ascending order: $\frac{3}{12},\frac{3}{7},\frac{3}{10},\frac{3}{4}$

• A. $\frac{3}{12}<\frac{3}{7}<\frac{3}{10}<\frac{3}{4}$
• B. $\frac{3}{12}<\frac{3}{10}<\frac{3}{7}<\frac{3}{4}$
  
• C. $\frac{3}{4}<\frac{3}{12}<\frac{3}{10}<\frac{3}{7}$
• D. $\frac{3}{4},\frac{3}{7}<\frac{3}{10}<\frac{3}{12}$

Answer 1

The correct option is B

$\frac{3}{12}<\frac{3}{10}<\frac{3}{7}<\frac{3}{4}$

When fractions have the same numerator and different denominators, then greater the denominator, smaller will be the fraction. Hence, $\frac{3}{12}$ is the smallest fraction while $\frac{3}{4}$ is the largest.

Hence, the fractions in ascending order are:
$\frac{3}{12}<\frac{3}{10}<\frac{3}{7}<\frac{3}{4}$