Question

Arrange the following in ascending order.

i. $21\times (-34)\times (-12)$

ii. $(7\times 8)-9$

iii. $7\times (8-9)$

iv. $21\times (-34)\times \left(12\right)$

• A. i < ii < iii < iv
• B. ii < iii < i < iv
• C. iv < i < iii < ii
• D. iv < iii < ii < i

Answer 1

The correct option is D

iv < iii < ii < i

Here,

$21\times (-34)\times (-12)=8568$
$(7\times 8)-9=47$
$7\times (8-9)=-7$
$21\times (-34)\times \left(12\right)=-8568$

$\therefore -8568<-7<47<8568$