Arrange the following in correct order of acidic strength.
(I) $C H_{3} N O_{2}$ (II) $N O_{2} C H_{2} - N O_{2}$
(III) $C H_{3} - C H_{2} - N O_{2}$ (IV) $N O_{2} - C | H N O_{2} - N O_{2}$

IV > II > I > III

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IV > II > III > I

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III > I > II > IV

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III > I > IV > II

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Solution

The correct option is A IV > II > I > III
$- I$ effect of $N i t r o$ group increase the acidity of substituted alkanes. The higher number of $N O_{2}$ groups increases the $- I$ effect therefore $T r i n i t r o - m e t h a n e (C H (N O_{2})_{3})$ is most acidic because three $N O_{2}$ groups show maximum electron withdrawing $- I$ effect which increase the acidic strength of alkylic hydrogen. $C H_{3}$ shows $+ I$ effect that decreases the acidic strength.
The order of acidic strength is $I V > I I > I > I I I$

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