Arrange the following in decreasing order of their basic strength: C6H5NH2,C2H5NH2,(C2H5)2NH,NH3
A
(C2H5)2NH>C2H5NH2>NH3>C6H5NH2
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B
C2H5NH2>(C2H5)2NH>NH3>C6H5NH2
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C
C2H5NH2>C6H5NH2>(C2H5)2NH>NH3
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D
C2H5NH2>NH3>C6H5NH2>(C2H5)2NH>
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Solution
The correct option is A(C2H5)2NH>C2H5NH2>NH3>C6H5NH2 Ammonia is more basic than aniline as in aniline, the lone pair of electron of N atom is in resonance with benzene ring. Hence, it cannot be donated easily.
Ethyl amine is more basic than ammonia because in ethyl amine, the +I effect of ethyl group increases the electron density on N.
Diethylamine is most basic due to +I effect of two ethyl groups.
Hence the decreasing order of basic stength is: (C2H5)2NH>C2H5NH2>NH3>C6H5NH2