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Question

Arrange the following in decreasing order of their boiling points:
(1) n-butane 
(2) $$2$$-methyl butane
(3) n-pentane 
(4) $$2,2$$-dimethyl propane 


A
1>2>3>4
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B
2>3>4>1
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C
4>3>2>1
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D
3>2>4>1
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Solution

The correct option is D 3>2>4>1
Boiling point is directly proportional to molar mass and surface area . It decreases on branching because surface area decreases. Hence , n-pentane has the highest and n-butane has the lowest boiling points and in rest two branching is there , therefore $$2$$-methyl butane has higher boiling point than $$2,2$$-dimethylpropane. 

Hence, Option "D" is the correct answer.

1660671_1794661_ans_b873f57d56a84cee913a03d32aadee83.png

Chemistry

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