Arrange the following in decreasing order of their boiling points: (1) n-butane (2) 2-methyl butane (3) n-pentane (4) 2,2-dimethyl propane
A
1>2>3>4
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B
2>3>4>1
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C
4>3>2>1
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D
3>2>4>1
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Solution
The correct option is D 3>2>4>1 Boiling point is directly proportional to molar mass and surface area . It decreases on branching because surface area decreases. Hence , n-pentane has the highest and n-butane has the lowest boiling points and in rest two branching is there , therefore 2-methyl butane has higher boiling point than 2,2-dimethylpropane.