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Question

Arrange the following in decreasing order of their boiling points:
(1) n-butane
(2) 2-methyl butane
(3) n-pentane
(4) 2,2-dimethyl propane

A
1>2>3>4
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B
2>3>4>1
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C
4>3>2>1
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D
3>2>4>1
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Solution

The correct option is D 3>2>4>1
Boiling point is directly proportional to molar mass and surface area . It decreases on branching because surface area decreases. Hence , n-pentane has the highest and n-butane has the lowest boiling points and in rest two branching is there , therefore 2-methyl butane has higher boiling point than 2,2-dimethylpropane.

Hence, Option "D" is the correct answer.

1660671_1794661_ans_b873f57d56a84cee913a03d32aadee83.png

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