Arrange the following in descending order-A - -12-5 - 5B - -29-5- - -6-2-C - -16-5- - 7D - -13- - -7-

Given: A = | 12/5|+ 5 nbsp; nbsp; = 12/5 + 5 nbsp; nbsp; nbsp;= 12+25/5 nbsp; nbsp; nbsp;= 37/5 B nbsp; = |29/5| |6/2| nbsp; nb ...

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Standard VI

Mathematics

BODMAS

Arrange the f...

Question

Arrange the following in descending order:

A = |- $\frac{12}{5}$ |+ 5

B = | $\frac{29}{5}$ | - | $\frac{6}{2}$ |

C = | $\frac{16}{5}$ | + 7

D = |-13| - |7|

A> B > C > D

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B > A > C > D

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C > A > B > D

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C > B > A > D

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Solution

The correct option is C C > A > B > D
Given:
A = $| - \frac{12}{5} | + 5$
= $\frac{12}{5} + 5$
= $\frac{12 + 25}{5}$
= $\frac{37}{5}$

B = | $\frac{29}{5}$ | - | $\frac{6}{2}$ |
= $\frac{29}{5}$ - 3
= $\frac{29 - 15}{5}$
= $\frac{14}{5}$

C = | $\frac{16}{5}$ | + 7
= $\frac{16 + 35}{5}$
= $\frac{51}{5}$

D = |-13| - |7|
= 13 - 7
= 6
= $\frac{30}{5}$

Hence, C > A > B > D

Therefore, option (c) is the correct answer.

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Similar questions

Q. Arrange following fractions in descending order.

\frac{5}{8}, \frac{7}{12}, \frac{3}{4} a n d \frac{13}{16}

Re-arrange suitably and find the sum in each of the following :

(i) $\frac{11}{12} + \frac{- 17}{3} + \frac{11}{2} + \frac{- 25}{2}$

(ii) $\frac{- 6}{7} + \frac{- 5}{6} + \frac{- 4}{9} + \frac{- 15}{7}$

(iii) $\frac{3}{5} + \frac{7}{3} + \frac{9}{5} + \frac{- 13}{15} + \frac{- 7}{3}$

(iv) $\frac{4}{13} + \frac{- 5}{8} + \frac{- 8}{13} + \frac{9}{13}$

(v) $\frac{2}{3} + \frac{- 4}{5} + \frac{1}{3} + \frac{2}{5}$

(vi) $\frac{1}{8} + \frac{5}{12} + \frac{2}{7} + \frac{7}{12} + \frac{9}{7} + \frac{- 5}{16}$

Verify the following :

(i) $\frac{3}{7} \times (\frac{5}{6} + \frac{12}{13}) = (\frac{3}{7} \times \frac{5}{6}) + (\frac{3}{7} \times \frac{12}{13})$
(ii) $\frac{- 15}{4} \times (\frac{3}{7} + \frac{- 12}{5}) = (\frac{- 15}{4} \times \frac{3}{7}) + (\frac{- 15}{4} \times \frac{- 12}{5})$
(iii) $(\frac{- 8}{3} + \frac{- 13}{12}) \times \frac{5}{6} = (\frac{- 8}{3} \times \frac{5}{6}) + (\frac{- 13}{12} \times \frac{5}{6})$
(iv) $\frac{- 16}{7} \times (\frac{- 8}{9} + \frac{- 7}{6}) = (\frac{- 16}{7} \times \frac{- 8}{9}) + (\frac{- 16}{7} \times \frac{- 7}{6})$

Q. Question 126
Arrange the numbers

\frac{1}{4}, \frac{13}{16}, \frac{5}{8}

in the descending order.

Q. Arrange the following in descending order.

\frac{5}{2}

\frac{3}{2}

\frac{7}{2}

\frac{9}{5}

\frac{9}{8}

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Arrange the following in descending order: A = |-125 |+ 5 B = |295| - |62| C = |165| + 7 D = |-13| - |7|

The correct option is C C > A > B > DGiven: A = |−125|+5 = 125+5 = 12+255 = 375 B = |295| - |62| = 295 - 3 = 29−155 = 145 C = |165| + 7 = 16+355 = 515 D = |-13| - |7| = 13 - 7 = 6 = 305 Hence, C > A > B > D Therefore, option (c) is the correct answer.

Arrange the following in descending order:

A = |- $\frac{12}{5}$ |+ 5

B = | $\frac{29}{5}$ | - | $\frac{6}{2}$ |

C = | $\frac{16}{5}$ | + 7

D = |-13| - |7|