Question

Arrange the following in descending order:
$\frac{1}{5},\frac{3}{7},\frac{7}{10}$

Answer 1

Given: $\frac{1}{5},\frac{3}{7},\frac{7}{10}$

Taking their LCM,

$\therefore$ The LCM is $5\times 2\times 7=70$

$\Rightarrow \frac{1}{5}\times \frac{14}{14}=\frac{14}{70}$

$\Rightarrow \frac{3}{7}\times \frac{10}{10}=\frac{30}{70}$

$\Rightarrow \frac{7}{10}\times \frac{7}{7}=\frac{49}{70}$

Since, $14<30<49$

$\therefore \frac{14}{70}<\frac{30}{70}<\frac{49}{70}$

$\Rightarrow \frac{1}{5}<\frac{3}{7}<\frac{7}{10}$

Thus, descending order of the fractions is $\frac{7}{10},\frac{3}{7},\frac{1}{5}$