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Question

Arrange the following in increasing order of oxidation states of Mn,
K2MnO4,MnO2,KMnO4

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Solution

K+=H,O2=2
K2MnO4
(+1×2)+x+(2×4)=0
2+x8=0
x=+6
MnO2

x+(2×2)=0
x=+4
KMnO4

(+1)+x+(2×4)=0
x=81=+7

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