Arrange the following in increasing order of the atomic sizes and give reasons
Na+ , Mg2+ , Al3+ , F- , O2- , C4-
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Solution
C4- with atomic number 6 has 6+4= e O2- witha tomic no. 8 has 8+2 = 10 electrons F- with atomic no. 9 has 9+1= 10 electrons Na+ with atomcatomic no. 11 has 9-1= 10 electrons Mg2+with atomcatomic no. 12 has 12-2= 10 electrons Al3+with atomcatomic no. 13 has 13-3= 10 electrons Since all these ions have 10 electrons in their shell therefore these are isoelectronic speicies The more + the charge, the smaller the ionic radius. Remember that - means adding electrons. These electrons go in the outermost shells. Also, when an atom loses electrons, it clings ever more tightly to the ones it has left, further reducing the ionic radius. therefore the order of ionic radii will be →