Arrange the following in the decreasing order of boiling point:
i) $C_{2} H_{5} O H$
ii) $(C H_{3})_{2} N H$
iii) $C_{2} H_{5} N H_{2}$

i > ii > iii

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ii > i > iii

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iii > i > ii

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iii > ii > i

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Solution

The correct option is A i > ii > iii
All the given compounds have intermolecular hydrogen bonding due to which their boiling points are higher. $C_{2} H_{5} O H$ possesses the strongest hydrogen bonding because the $O$ is more electron negative than $N$ in other compounds. Therefore it has the highest boiling point.

In $(C H_{3})_{2} N H$ and $C_{2} H_{5} N H_{2}$ , the latter has a longer alkyl chain which makes hydrogen bonding weaker.

Hence the order of boiling points is $i > i i > i i i$

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