Arrange the following in the decreasing order of their coagulation power: $A l^{3 +}, N a^{+}, C a^{2 +}$

A l^{3 +} = C a^{2 +} = N a^{+}

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N a^{+} > C a^{2 +} > A l^{3 +}

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N a^{+} > A l^{3 +} > C a^{2 +}

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A l^{3 +} > C a^{2 +} > N a^{+}

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Solution

The correct option is D $A l^{3 +} > C a^{2 +} > N a^{+}$
Greater the valency of the flocculating ion added, greater is its power to cause precipitation (Hardy Schulze rule).

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A l^{3 +}, N a^{+}, C a^{2 +}

A l^{3 +}, N a^{+}, C a^{2 +}

{N a}^{+}, {C a}^{2 +}, {M g}^{2 +}, {A l}^{3 +}

{C a}^{2 +} < {N a}^{+} < {M g}^{2 +} < {A l}^{3 +}

A l^{3 +} > B a^{2 +} > N a^{+}

{N a}^{+}, {A l}^{3 +}

{B a}^{2 +}

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