Arrange the following in the increasing order of the number of gram molecule in the given masses:

(iv)<(ii)<(i)<(iii)

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(i)<(ii)<(iii)<(iv)

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(iii)<(i)<(ii)<(iv)

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(ii)<(iv)<(i)<(iii)

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Solution

The correct option is A (iv)<(ii)<(i)<(iii)
(i) $50 g$ of $N a_{2} S O_{4} ⟶ 142 =$ Molecular weight of $N a_{2} S O_{4}$
(ii) $32 g$ of $S O_{2} ⟶ 32 + 64 = 96 =$ Molecular weight of $S O_{2}$
(iii) $40 g$ of $K B r ⟶ 119 = 120 =$ Molecular weight of $K B r$
(iv) $10 g$ of $H e = 4 g m =$ Molecular weight of $H e$

$(i v) < (i i) < (i) < (i i i)$ is the order.

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