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Physical Properties

Arrange the f...

Question

Arrange the following in the increasing order of their boiling point:

$C_{2} H_{5} O H, {(C H}_{3})_{2} N H, C_{2} H_{5} {N H}_{2}$

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Solution

Boiling point depends upon $H -$ bonding present in compound. Boiling point will be higher if extent of $H -$ bonding is more in the compound.
$(C H_{3})_{2} N H$ has only one $H -$ atom $C_{2} H_{5} N H_{2}$ has two $H -$ atom then $C_{2} H_{5} N H_{2}$ has more extensive $H -$ bonding than $(C H_{3})_{2} N H$ .
Therefore the boiling point of $C_{2} H_{5} N H_{2}$ is more than $(C H_{3})_{2} N H .$
$^{'} O^{'}$ is more electromagnet iv than $^{'} N^{'}$ . Thus, $C_{2} H_{5} O n$ has more stronger $n -$ bond than $C_{2} H_{5} N H_{2}$ and $(C H_{3})_{2} N H$
order $(C H_{3})_{2} N H < C_{2} H_{5} N H_{2} < C_{2} H_{5} O H$

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