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Question
Arrange the following in the increasing order of their boiling point:
C2H5OH, (CH3)2NH, C2H5NH2
Arrange the following in the increasing order of their boiling point:
C2H5OH, (CH3)2NH, C2H5NH2
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Solution
Boiling point depends upon H−bonding present in compound. Boiling point will be higher if extent of H−bonding is more in the compound.(CH3)2NH has only one H−atom C2H5NH2 has two H−atom then C2H5NH2 has more extensive H−bonding than (CH3)2NH.Therefore the boiling point of C2H5NH2 is more than (CH3)2NH.′O′ is more electromagnet iv than ′N′. Thus, C2H5On has more stronger n−bond than C2H5NH2 and (CH3)2NHorder (CH3)2NH<C2H5NH2<C2H5OH
Boiling point depends upon H−bonding present in compound. Boiling point will be higher if extent of H−bonding is more in the compound.
(CH3)2NH has only one H−atom C2H5NH2 has two H−atom then C2H5NH2 has more extensive H−bonding than (CH3)2NH.
Therefore the boiling point of C2H5NH2 is more than (CH3)2NH.
′O′ is more electromagnet iv than ′N′. Thus, C2H5On has more stronger n−bond than C2H5NH2 and (CH3)2NH
order (CH3)2NH<C2H5NH2<C2H5OH
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