Arrange the following in the increasing reactivity: $I_{2} < {B r}_{2} < {C l}_{2} < F_{2}$
If true enter 1, else enter 0.

Open in App

Solution

Halogens are highly reactive. This reactivity is due to high electronegativity and high effective nuclear charge. Halogens can gain an electron by reacting with atoms of other elements.
Fluorine is one of the most reactive elements. It reacts with otherwise inert materials such as glass, and it forms compounds with the heavier noble gases.
So the reactivity order is:
$I_{2} < {B r}_{2} < {C l}_{2} < F_{2}$

Suggest Corrections

Similar questions

I_{2}, {B r}_{2}, {C l}_{2}, F_{2}

I_{2} < {B r}_{2} < {C l}_{2} < F_{2}

F_{2} < {C l}_{2} < O_{2} < N_{2}

F_{2} < C l_{2} < B r_{2} < I_{2}

F_{2}, C l_{2}, B r_{2}, I_{2},

{B r}^{-}

I^{-}

{C l}_{2}

{B r}_{2}

I_{2}

Join BYJU'S Learning Program