Arrange the following in their decreasing order of acidity.

I I I > I V > I > I I

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

I > I I > I I I > I V

No worries! We‘ve got your back. Try BYJU‘S free classes today!

I V > I I I > I I > I

No worries! We‘ve got your back. Try BYJU‘S free classes today!

I I > I I I > I > I V

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $I I I > I V > I > I I$
The decreasing order of acidity is $I I I > I V > I > I I$ .
In (III) $+ I$ effect of two $M e$ groups makes it most basic
In (I) electron-withdrawing effect of the carbonyl group makes it less basic than ammonia.
In (II) electron-withdrawing effect of two ( $C = O$ ) groups makes it least basic.

Suggest Corrections

Similar questions

I . Z n O

I I . K_{2} O

I I I . P_{2} O_{5}

I V . M g O

H_{2} S O_{4}

I . T l_{2} O

I I . A l_{2} O_{3}

I I I . T l_{2} O_{3}

I V . G a_{2} O_{3}

50^{\circ}

Order of decreasing acidity of

$(i) H C O O H (i i) C H_{3} C O O H (i i i) C l_{2} C H C O O H (i v) C F_{3} C O O H i s$

Join BYJU'S Learning Program