Arrange the following isomers of hexadiene in order of increasing stability(least stable first):

I, II, III, IV

No worries! We‘ve got your back. Try BYJU‘S free classes today!

II, IV, I, III

No worries! We‘ve got your back. Try BYJU‘S free classes today!

I, III, IV, II

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

IV, II, III, I

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A I, III, IV, II
For the given isomers of hexadiene, the order of decreasing stability (least stable last) is
$I > I I I > I V > I I$ .
I is trans-trans, therefore most stable and II is cis-cis, therefore least stable.
Hence, the option C is correct answer. Note: trans double bond is more stable than cis double bond.

Suggest Corrections

Similar questions

Q. Arrange the following compounds in order of increasing dipole moment.
(I) Toluene
(II) m - dichlorobenzene
(III) o - dichlorobenzene
(IV) p - dichlorobenzene

Q. Make the correct match
A

V
I

V
V

Arrange the following alcohols in order of increasing ease of dehydration
$C H_{3} C H_{2} O H$ $C_{6} H_{5} C H_{2} O H$
I II

$C l_{3} C C H_{2} O H$ $F_{3} C C H_{2} O H$
III IV

Q. Identify the rate of reaction of given compounds in

E_{2}

reactions

Q. Arrange (I)

C e^{3 +}

, (II)

L a^{3 +}

, (III)

P m^{3 +}

and (IV)

Y b^{3 +}

in increasing order of their ionic radii

Join BYJU'S Learning Program