Arrange the following members of the homologous series of alcohols in decreasing order of boiling point.

I>IV>III>II

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IV>III>II>I

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I>II>III>IV

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IV>I>II>III

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Solution

The correct option is D IV>I>II>III

The members of a homologous series have the same chemical properties but the physical properties such as melting point, boiling point, etc., increase in the homologous series with an increase in the molecular mass.

As we go in increasing order in a homologous series, one $C H_{2}$ unit gets added.

The compound $C H_{3} C H_{2} C H_{2} C H_{2} C H_{2} O H$ will have the highest boiling point and then $C H_{3} C H_{2} C H_{2} C H_{2} O H$ , $C H_{3} C H_{2} C H_{2} O H$ , $C H_{3} C H_{2} O H$ .

So, the decreasing order of boiling points of members of alcohols is IV>I>II>III. The correct option is D.

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Similar questions

Arrange the following compounds in increasing order of their boiling points.

CH₃CHO, CH₃CH₂OH, CH₃OCH₃, CH₃CH₂CH₃

Assertion (A): Following are the members of a homologous series: CH₃OH, CH₃CH₂OH, CH₃CH₂CH₂OH .

Reason (R): A series of compounds with the same functional group but differing by – CH₂ – unit is called a homologous series.

C H_{3} C H_{2} O H, H O C H_{2} C H_{2} O H, C H_{3} C H_{2} C l

C H_{3} C H_{2} C H_{2} C H O, C H_{3} C H_{2} C H_{2} C H_{2} O H, H_{5} C_{2} - O - C_{2} H_{5}, C H_{3} C H_{2} C H_{2} C H_{2} C H_{3}

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