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Ionization Enthalpy

Arrange the f...

Question

Arrange the following metals in the order in which they displace each other from the solution of their salts.
$A l, C u, F e, M g$ and $Z n$

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Solution

The order in which the metals displace each other from the solution of their salts is $M g, A l, Z n, F e, C u$ . Thus, more electropositive $M g$ can displace less electropositive $C u$ .

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Q. Arrange the following metals in which they displace each other from the solutions of their salts in decreasing order:

A l, C u, F e, M g

Z n

E_{A l^{3} + / A l}^{0} + - 1.66 V, E_{C u^{2} + / C u}^{0} = + 0.34 V

,

E_{F e^{2} + / F e}^{0} = - 0.44 V, E_{M g^{2} + / M g}^{0} = - 1.40 V

E_{Z n^{2} + / Z n}^{0} = - 0.76 V

Q. (i) Arrange the following metals in an increasing order of their reactivity towards water: Zn, Fe, Mg, Na.
(ii) Arrange the following in increasing order of their oxides to get reduced with carbon: Al, Na, Fe, Cu.
(iii) Arrange the following metals in order of decreasing order of their chemical reactivity: Mg, Ca, Cu, Fe, Na, Zn, Pb.

C u, A g, F e

Z n

, the metal which can displace all others from their salt solution is:

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