Arrange the following molecules in increasing order of energy : $N_{2}, O_{2}, C l_{2}, F_{2}$ .

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Solution

$N_{2}$ has triple bond between $N$ atoms.
$O_{2}$ has double bond between $O$ atoms.
$F_{2}$ and $C l_{2}$ has single bonds between the atoms.
More the number of bonds between atoms, more will be the bond energy. Between $F_{2}$ and $C l_{2}$ , $C l_{2}$ has more bond energy because in $F_{2}$ , the atoms are closer and repulsions are more. So, bond energy of $F_{2}$ is less.
$∴$ Order of bond energies= $N_{2} > O_{2} > C l_{2} > F_{2}$

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