Arrange the following molecules in increasing order of intermoleculat force $C_{2} H_{6}, C H_{3} N H_{2}, C H_{3} F$ and $C H_{2} F_{2}$ .

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Solution

The intermolecular force of attraction is in the order
$C H_{2} F_{2} > C H_{3} F > C H_{3} N H_{2} > C_{2} H_{6}$
Due to higher polarity and higher molecular mass.
Molecular mass of $C H_{2} F_{2} = 12 + 2 + 38 = 62$ g
Molecular mass of $C H_{3} F = 12 + 3 + 19 = 34$ g
Molecular mass of $C H_{3} N H_{2} = 12 + 5 + 14 = 31$ g
Molecular mass of $C_{2} H_{6} = 24 + 6 = 30$ g

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