Arrange the following molecules in the decreasing order of bond angle.
$(i) N H_{3} (i i) C H_{4} (i i i) B F_{3} (i v) B e C l_{2}$

i > i i > i i i > i v

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i v > i i i > i i > i

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i v > i i i > i > i i

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i i > i > i i i > i v

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Solution

The correct option is B $i v > i i i > i i > i$

So, the order of bond angle is $i v > i i i > i i > i$ .

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