Question

Arrange the following numbers in ascending order:

$1.7\times {10}^5,-1.8\times {10}^5,1.7\times {10}^{10}$

• A. $1.7\times {10}^{10},1.7\times {10}^5,-1.8\times {10}^5$
• B. $1.7\times {10}^5,-1.8\times {10}^5,1.7\times {10}^{10}$
• C. $-1.8\times {10}^5,1.7\times {10}^5,1.7\times {10}^{10}$
• D. $1.7\times {10}^5,1.7\times {10}^{10},-1.8\times {10}^5$

Answer 1

The correct option is C

$-1.8\times {10}^5,1.7\times {10}^5,1.7\times {10}^{10}$

We know that negative numbers are always less than the positive numbers. So, $-1.8\times {10}^5$ is the least number among the given numbers

$1.7\times {10}^5=1.7\times 100000=170000$

$1.7\times {10}^{10}=1.7\times 10000000000=17000000000$

$\therefore 1.7\times {10}^5<1.7\times {10}^{10}$

The ascending order: $-1.8\times {10}^5<1.7\times {10}^5<1.7\times {10}^{10}$