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Question

Arrange the following numbers in ascending order:

909, 99, 9090, 1009

A
99, 9090, 909, 1009
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B
1009, 909, 9090, 99
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C
9090, 1009, 909, 99
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D
99, 909, 1009, 1009
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Solution

The correct option is D 99, 909, 1009, 1009
While arranging the numbers in ascending order, we start with the smallest numbers on the left to the largest numbers on the right.

In the given numbers, 9090 and 1009 are 4-digit numbers. So, they are greater than the other two numbers.

Between 9090 and 1009, when we look at their place values

Th H T U
9 0 9 0
1 0 0 9

In thousands place, 9 > 1
Therefore, 9090 > 1009

Between the other numbers 909 and 99
Since 909 is a 3-digit number and 99 is a 2-digit number,
909 > 99

So, the numbers arranged in ascending order looks like

99, 909, 1009, 9090

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