Question

Arrange the following numbers in ascending order:

$\frac{-1}{3}$ $-\frac{2}{9}$ $-\frac{4}{3}$

Answer 1

Here all three given numbers are negative.

Step 1: Write them without their signs
$\frac{1}{3}$ $\frac{2}{9}$ $\frac{4}{3}$

Step 2: Change them into like fractions and add inequality signs:
$\frac{1\times 3}{3\times 3}$ $\frac{2}{9}$ $\frac{4\times 3}{3\times 3}$
$\frac{2}{9}<\frac{3}{9}<\frac{12}{9}$

Step 3: Add negative signs and reverse the inequality signs.
$-\frac{2}{9}>-\frac{3}{9}>-\frac{12}{9}$
So, option D is correct.​​