Question

Arrange the following numbers in suitable groups and then add: $1849,608,392$ and $2151$.

Answer 1

Step $1:$ Firstly see, whose numbers have unit place digit makes sum$10$.

In this case $9+1=10$

Also, $8+2=10$

So we add, $1849+2151=4000$

$608+392=1000$

Step $2:$ $(1849+2151)+(608+392)$

$$\begin{gathered} =4000+1000 \\ =5000 \end{gathered}$$

Hence, the answer is$5000$.