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Byju's Answer
Standard XII
Mathematics
Transpose of a Matrix
Arrange the f...
Question
Arrange the following options in ascending order.
(Smallest value at the top)
A
4 times 3
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B
3 times 6
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C
5 times 2
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D
7 times 4
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Solution
4
times
3
=
3
+
3
+
3
+
3
=
12
3
times
6
=
6
+
6
+
6
=
18
5
times
2
=
2
+
2
+
2
+
2
+
2
=
10
7
times
4
=
4
+
4
+
4
+
4
+
4
+
4
+
4
=
28
Since
10
<
12
<
18
<
28
,
we have
5
times
2
<
4
times
3
<
3
times
6
< 7 times 4.
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