Arrange the following oxides in the decreasing orders of their basic strength.
$I . T l_{2} O$ $I I . A l_{2} O_{3}$ $I I I . T l_{2} O_{3}$ $I V . G a_{2} O_{3}$

I > I I I > I V > I I

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I I > I V > I I I > I

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I I I > I > I I > I V

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I V > I I > I > I I I

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Solution

The correct option is A $I > I I I > I V > I I$
Since charges on the cation II, III, IV are same, we have to check the size of the cation. Order of thesize of those cation are $T l^{3 +} > G a^{3 +} > A l^{3 +}$ .
So correct order of basic oxides is,
$T l_{2} O > T l_{2} O_{3} > G a_{2} O_{3} > A l_{2} O_{3}$

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