Question

Arrange the following particle in increasing order of values of e/m ratio : electron (e), proton (p), neutron (n) and $\alpha$-particle $\left(\alpha \right)$.

• A. n, p, e, $\alpha$
• B. n, $\alpha$, p, e
• C. n, p, $\alpha$, e
• D. e, p, n, $\alpha$

Answer 1

Answer: (B)

n, $\alpha$, p, e

$n<\alpha <p<e$

e/m of n = 0
$e/mof\alpha =\frac{9.58\times {10}^4}{2}c/g$
e/m of p = $9.58\times {10}^{4}c/g$
e/m of e = $1.7588\times {10}^{8}c/g$