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Question

Arrange the following particle in increasing order of values of e/m ratio : electron (e), proton (p), neutron (n) and $$\displaystyle \alpha $$-particle $$\displaystyle (\alpha) $$.


A
n, p, e, α
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B
n, α, p, e
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C
n, p, α, e
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D
e, p, n, α
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Solution

The correct option is A n, $$\displaystyle \alpha $$, p, e
$$\displaystyle n< \alpha < p< e$$            
e/m of n = 0
$$\displaystyle e/m\: \: of\: \: \alpha =\frac{9.58\times 10^{4}}{2}c/g$$
e/m of p = $$\displaystyle 9.58\times 10^{4}\: \: c/g$$
e/m of e = $$\displaystyle 1.7588\times 10^{8}\: \: c/g$$

Chemistry

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