Arrange the following physical quantities in the decreasing order of dimension of length.
I. Density
II. Pressure
III. Power
IV. Impulse

I, II, III, IV

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III, II, I, IV

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IV, I, II, III

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III, IV, II, I

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Solution

The correct option is D III, IV, II, I
$D e n s i t y = \frac{M a s s}{l e n g t h} = M^{1} L^{- 3} T^{0}$
$P r e s s u r e = \frac{f o r c e}{A r e a} = \frac{M^{1} L^{1} t^{- 2}}{L^{2}} = M^{1} L^{- 1} T^{- 2}$
$P o w e r = F \times v = M^{1} L^{1} T^{- 2} \times L T^{- 1} = M^{1} L^{2} T^{- 3}$
$I m p u l s e = f \times t = M^{1} L^{1} T^{- 2} \times T^{1} = M^{1} L^{1} T^{- 1}$
Hence, option D is correct.

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