Arrange the following rational number in descending order 1-5-1-6- - -7-6-1 - -1-2 3-5-8-15-4

The correct option is C | 7/6+1 |,1/5+1/ 6, ( 1/2 )^3,5/8÷ 15/4 1/5+1/ 6=1/5 1/6=6 5/30=1/30 | 7/6+1 |= | 7+6/6 |= | 1/6, |=1/6 ( ...

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Byju's Answer

Standard VI

Mathematics

Fractions on the Number Line

Arrange the f...

Question

Arrange the following rational number in descending order
$\frac{1}{5} + \frac{1}{- 6}, ∣ ∣ ∣ - \frac{7}{6} + 1 ∣ ∣ ∣, {(- \frac{1}{2})}^{3}, \frac{5}{8} \div \frac{- 15}{4}$

\frac{1}{5} + \frac{1}{- 6}, {(- \frac{1}{2})}^{3}, \frac{5}{8} \div \frac{- 15}{8}, ∣ ∣ ∣ - \frac{7}{6} + 1 ∣ ∣ ∣

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{(- \frac{1}{2})}^{3}, \frac{1}{5} + \frac{1}{- 6}, \frac{5}{8} \div \frac{- 15}{4}, ∣ ∣ ∣ - \frac{7}{6} + 1 ∣ ∣ ∣

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∣ ∣ ∣ - \frac{7}{6} + 1 ∣ ∣ ∣, \frac{1}{5} + \frac{1}{- 6}, {(- \frac{1}{2})}^{3}, \frac{5}{8} \div \frac{- 15}{4}

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\frac{5}{6} \div \frac{- 15}{4}, ∣ ∣ ∣ - \frac{7}{6} + 1 ∣ ∣ ∣, \frac{1}{5} + \frac{1}{- 6}, {(- \frac{1}{2})}^{3}

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Solution

The correct option is C $∣ ∣ ∣ - \frac{7}{6} + 1 ∣ ∣ ∣, \frac{1}{5} + \frac{1}{- 6}, {(- \frac{1}{2})}^{3}, \frac{5}{8} \div \frac{- 15}{4}$
$\frac{1}{5} + \frac{1}{- 6} = \frac{1}{5} - \frac{1}{6} = \frac{6 - 5}{30} = \frac{1}{30}$

$∣ ∣ ∣ - \frac{7}{6} + 1 ∣ ∣ ∣ = ∣ ∣ ∣ - \frac{7 + 6}{6} ∣ ∣ ∣ = ∣ ∣ ∣ - \frac{1}{6}, ∣ ∣ ∣ = \frac{1}{6}$

${(- \frac{1}{2})}^{3} = - (\frac{1}{8})$

$\frac{5}{8}\div \frac{-15}{4}=\frac{5}{8}\times \frac{-4}{15}=-\frac{1}{6}$

$∴$ Arranged in descending order the given numbers

are $\frac{1}{6}, \frac{1}{30}, - \frac{1}{8}, - \frac{1}{6}$

as $\frac{20}{120}, \frac{4}{120}, \frac{- 15}{120}, \frac{- 20}{120}$

i.e. $∣ ∣ ∣ - \frac{7}{6} + 1 ∣ ∣ ∣, \frac{1}{5} + \frac{1}{- 6}, {(- \frac{1}{2})}^{3}, \frac{5}{8} \div \frac{- 15}{4}$

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Similar questions

Q. Simplify :

\frac{2 \frac{3}{4}}{1 \frac{5}{6}} \div \frac{7}{8} \times (\frac{1}{3} + \frac{1}{4}) + \frac{5}{7} \div \frac{3}{4}

\frac{3}{7}

Q. Simplify this

\frac{1}{\sqrt{9} - \sqrt{8}} - \frac{1}{\sqrt{8} - \sqrt{7}} + \frac{1}{\sqrt{7} - \sqrt{6}} - \frac{1}{\sqrt{6} - \sqrt{5}} + \frac{1}{\sqrt{5} - \sqrt{4}}

$\frac{1}{(\sqrt{9} - \sqrt{8})} - \frac{1}{(\sqrt{8} - \sqrt{7})} + \frac{1}{(\sqrt{7} - \sqrt{6})} - \frac{1}{(\sqrt{6} - \sqrt{5})} + \frac{1}{(\sqrt{5} - \sqrt{4})}$ is equal to:

$\frac{1}{1 + \sqrt{2}} + \frac{1}{\sqrt{2} + \sqrt{3}} + \frac{1}{\sqrt{3} + \sqrt{4}} + \frac{1}{\sqrt{4} + \sqrt{5}} + \frac{1}{\sqrt{5} + \sqrt{6}} + \frac{1}{\sqrt{6} + \sqrt{7}} + \frac{1}{\sqrt{7} + \sqrt{8}} + \frac{1}{\sqrt{8} + \sqrt{9}} =$ __________.

Verify the following :

(i) $\frac{3}{7} \times (\frac{5}{6} + \frac{12}{13}) = (\frac{3}{7} \times \frac{5}{6}) + (\frac{3}{7} \times \frac{12}{13})$
(ii) $\frac{- 15}{4} \times (\frac{3}{7} + \frac{- 12}{5}) = (\frac{- 15}{4} \times \frac{3}{7}) + (\frac{- 15}{4} \times \frac{- 12}{5})$
(iii) $(\frac{- 8}{3} + \frac{- 13}{12}) \times \frac{5}{6} = (\frac{- 8}{3} \times \frac{5}{6}) + (\frac{- 13}{12} \times \frac{5}{6})$
(iv) $\frac{- 16}{7} \times (\frac{- 8}{9} + \frac{- 7}{6}) = (\frac{- 16}{7} \times \frac{- 8}{9}) + (\frac{- 16}{7} \times \frac{- 7}{6})$

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Arrange the following rational number in descending order15+1−6,∣∣∣−76+1∣∣∣,(−12)3,58÷−154

Arrange the following rational number in descending order
$\frac{1}{5} + \frac{1}{- 6}, ∣ ∣ ∣ - \frac{7}{6} + 1 ∣ ∣ ∣, {(- \frac{1}{2})}^{3}, \frac{5}{8} \div \frac{- 15}{4}$