Question

Arrange the following rational number in descending order
$\frac{17}{-30},\frac{11}{-15},\frac{-7}{10},\frac{3}{5}.$

Answer 1

Rational numbers can be arranged in descending

all ascending order by making their denominates equal.

Therefore, LCM of 30, 15, 10 and 5 is 30.

So, $\frac{-17}{30}=\frac{-17}{30};\frac{-7}{10}=\frac{21}{30}$

$\frac{-11}{15}=\frac{-22}{30};\frac{3}{5}=\frac{18}{30}$

so, in descending order $\to$

$\frac{18}{30}>\frac{-17}{30}>\frac{-21}{30}>\frac{-22}{30}$

$=\frac{3}{5}>\frac{-17}{30}>\frac{-7}{10}>\frac{-11}{15}$